# Two Waves Traveling In Opposite Directions On A Rope

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Two Waves Traveling In Opposite Directions On A Rope – Two waves moving in opposite directions produce a standing wave. The respective wave functions are given by `y_(1) = 4 sin (3x – 2 t)` and `y_(2) = 4 sin (3x + 2 t) cm` , where `x` and `y` are in cm

Solution: (a) When the two waves are added. The result is a standing wave whose mathematical representation is given by equation, with “A = 4.0 cm” and “k = 3.0 rad//cm,”

## Two Waves Traveling In Opposite Directions On A Rope `y = (2A sin kx) cos omegat = [(8.0 cm) sin 3.0 X] cos 2.0 t`

Therefore, the maximum displacement of particles at position ‘x = 2.3 cm’

`y_(max) = [(8.0 cm) sin 3.0x]_(x = 2.3 cm)`

`= (8.0 m) sin (6.9 rad) = 4.6 cm`

(b) Since `k = 2pi // lambda = 3.0 rad // cm`, we see that `lambda = 2pi // 3cm`. Therefore, the antinodes are located at

## Two Sinusoidal Waves Traveling In Opposite Directions Interf

`x = n((pi)/(6.0)) cm (n = 1, 3, 5, ……..)`

and the nodes are located at

`x = n (lambda)/(2-)((pi)/(3.0)) cm (n = 1, 2, 3, ………)` Step-by-step solution by experts to help you solve doubt and score good marks on exams.

#### Explain What Happens When Two Light Waves Traveling From Opposite Directions Of Displacement Meet?

The mathematical form of three traveling waves is given by

`Y_(1) = (2 cm) sin (3x-6t)`

`Y_(2) = (3cm) sin(4x-12t)`

And `Y_(3)=94 cm) sin(5x-11t)`

### Standing Waves By Vista Team123

of these waves,

Two waves traveling in a medium are given by `y_(1) = 2 sin(3pi t -pi/2 x)` and `y_(2) = 4 sin(6pit – (3pi)/2x) `

where `y_(1), y_(2)` and x are in cm and t is in seconds. The motion of a particle at x = 1 cm at time t = 1 s is: Find the resulting amplitude and phase difference between the resulting wave and the first wave, if the following waves intersect at a point, `y_(1) = (3 cm) sin omega t’,

## Solved Two Harmonic Waves Traveling In Opposite Directions

`y_(2) = (4 cm) sin (omega t + (pi)/(2)), y_(3) = (5 cm) sin (omega t + pi)`

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