Two Waves Traveling In Opposite Directions On A Rope – Two waves moving in opposite directions produce a standing wave. The respective wave functions are given by `y_(1) = 4 sin (3x – 2 t)` and `y_(2) = 4 sin (3x + 2 t) cm` , where `x` and `y` are in cm
Solution: (a) When the two waves are added. The result is a standing wave whose mathematical representation is given by equation, with “A = 4.0 cm” and “k = 3.0 rad//cm,”
Two Waves Traveling In Opposite Directions On A Rope
`y = (2A sin kx) cos omegat = [(8.0 cm) sin 3.0 X] cos 2.0 t`
Exam Summer 2020, Answers
Therefore, the maximum displacement of particles at position ‘x = 2.3 cm’
`y_(max) = [(8.0 cm) sin 3.0x]_(x = 2.3 cm)`
`= (8.0 m) sin (6.9 rad) = 4.6 cm`
(b) Since `k = 2pi // lambda = 3.0 rad // cm`, we see that `lambda = 2pi // 3cm`. Therefore, the antinodes are located at
Two Sinusoidal Waves Traveling In Opposite Directions Interf
`x = n((pi)/(6.0)) cm (n = 1, 3, 5, ……..)`
and the nodes are located at
`x = n (lambda)/(2-)((pi)/(3.0)) cm (n = 1, 2, 3, ………)`
Step-by-step solution by experts to help you solve doubt and score good marks on exams.
Explain What Happens When Two Light Waves Traveling From Opposite Directions Of Displacement Meet?
The mathematical form of three traveling waves is given by
`Y_(1) = (2 cm) sin (3x-6t)`
`Y_(2) = (3cm) sin(4x-12t)`
And `Y_(3)=94 cm) sin(5x-11t)`
Standing Waves By Vista Team123
of these waves,
Two waves traveling in a medium are given by `y_(1) = 2 sin(3pi t -pi/2 x)` and `y_(2) = 4 sin(6pit – (3pi)/2x) `
where `y_(1), y_(2)` and x are in cm and t is in seconds. The motion of a particle at x = 1 cm at time t = 1 s is:
Find the resulting amplitude and phase difference between the resulting wave and the first wave, if the following waves intersect at a point, `y_(1) = (3 cm) sin omega t’,
Solved Two Harmonic Waves Traveling In Opposite Directions
`y_(2) = (4 cm) sin (omega t + (pi)/(2)), y_(3) = (5 cm) sin (omega t + pi)`
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