**A Car Starts From Rest And Travels For 5.0 S** – The car starts from rest and works for a while with constant acceleration “alpha”, then with constant deceleration “beta” and stops. The movement time is “t”. Find the maximum speed it reaches.

The car starts from rest and travels for a time with a uniform acceleration a, then with a uniform deceleration `beta’ and stops. If the total time of the car is ‘t’, the maximum speed it reaches is given by

## A Car Starts From Rest And Travels For 5.0 S

A car starts from rest and travels a distance with uniform acceleration f, then travels at uniform speed during time t and finally stops with uniform delay `(f)/(2)’. If the total distance traveled is 5s. Then

#### How To Clean Your Car Interior Like A Pro

Starting from the resting place, the train travels a certain distance with a uniform acceleration “alpha”. It then moves with a constant lag of “beta” and finally stops again. If the total travel time is t, find (i) the maximum speed attained and (ii) the total distance traveled by the train.

A train reaches velocity v after starting from rest with uniform acceleration ‘alpha’. The train then travels at a constant speed for a while and eventually stops with a constant delay of “beta”. If the total displacement is s at time t, show that `t = (s)/(v)+(v)/(2) ((1)/alpha+(1)/(beta))

The car starts from the initial position with a constant acceleration “alpha” and reaches a maximum speed V. It travels at maximum speed for a while and keeps delaying the “beta” speed and stopping. If s is the total distance and t is the total travel time, then t=

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