**A Car Traveling At 30m S Runs Out Of Gas** – Step by step solutions by experts to help you clear doubts and score well in exams.

Hello everyone, if you are going to talk about this question, this question is about the brakes of a car that travels for 30 seconds in 30 seconds, its speed is reduced to 20 meters in 5 seconds, we have to calculate the resistance caused at the brakes, we have to also calculate the distance in the Pi S ok so what we get the initial speed of the car is only 30 meters per second and the final speed is only 20 meters per second when it takes to change that speed max is 5. second look so what we will find out is that we need to find the extension and distance traveled in the sky so ok let’s use this calculation be near you + 82 find the delay now we are 2030 now let acceleration and delay is to time is 5

## A Car Traveling At 30m S Runs Out Of Gas

Then I will have 5A as 20 – 30 going on -10 and this shows that the acceleration is nothing but – 2 meters per square second now this – shows that this is a reduction in the magnitude of the delay is 2 meters in the second square. now we need to find the distance traveled during this Pi S so we can use the equation with the equation V squared minus A squared B squared minus A squared = 22 Aas ok so this is the equation for cooking now we know we are nothing but 22 b square is nothing but 400 – the square will be 900 1 is to 2 in acceleration is to remove 2 in migration so from here we need to find the stop distance indicated by as soon as it comes out it will be – 500:-

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So now if you solve this you get like 250 with which is nothing but 125 M so the distance covered in those five seconds is nothing but 125 M I hope you understand thanks.

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